(4x^2-9)/(2x+3)=1

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Solution for (4x^2-9)/(2x+3)=1 equation: 



(4x^2-9)/(2x+3)=1

We move all terms to the left:

(4x^2-9)/(2x+3)-(1)=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R



We multiply all the terms by the denominator


(4x^2-9)-1*(2x+3)=0

We get rid of parentheses

4x^2-1*(2x+3)-9=0

We move all terms containing x to the left, all other terms to the right

4x^2-1*(2x+3)=9

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